
Andre C. answered 11/30/17
Tutor
5.0
(245)
The toughest Algebra problems are about to get super easy.
Think about this
Dana (d) paints a barn in 5 hours, so her rate of work is :
1/5 of a barn (b) in 1 hour, so set d =1/5b
Giovanni (g) paints a barn in 8 hours, so his rate of work is:
1/8 of a barn in 1 hour, so set g=1/8b
Now we want to know what happens when we combine Dana and Giovanni's hourly rates.
we have :
d+g = 1 hour of Dana and Giovanni's work
1b/5+1b/8=1
combine the fractions
8b/40 + 5b/40=1
13b/40=1 This is the combined rate of work for Dana and Giovanni.
Now just find b
b=40/13
thus it will take 40/13 hours of work to paint a barn if Dana and Giovanni do it together.