Write the equation of the line (in slope-intercept form) would be perpendicular to the line y=-1/3x-5 and that goes through the point (4, -1)?

Question

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Answer 1

y =-1/3 x -5

 

slope of this line is -1/3

 

slope of perpendicular line is -ve reciprocal so slope of perpendicular line is 3/1=3

 

y = mx+b

line goes through (4,-1)

substitute value of (x,y)=(4,-1)

-1 =3(4)+b

-1=12+b

b=-13

 

equation of line is

y=3x-13