J.R. S. answered 11/29/17
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Balanced equation for complete combustion of ethane.
2C2H6 + 7O2 ==> 4CO2 + 6H2O
moles C2H6 burned = 27.6 g x 1 mole/30 g = 0.92 moles
Theoretical yield of CO2 = 0.92 moles C2H6 x 4 mole CO2/2 mole C2H6 = 1.84 moles CO2
Theoretical mass CO2 = 1.84 moles x 44 g/mole = 80.96 g
% yield = 76.7 g/80.96 g (x100%) = 94.7% yield