what is the mean of this binomial probability distribution?

Question

You are playing a card game in which you have a 0.25 probability of winning each hand. If you play 15 hands,what is the mean of this binomial probability distribution?

Answer 1

Hi Sheily,

 

For this case, we have that p = 0.25 and n = 15. Then, we can model this distribution as B(15,0.25). The expected value, otherwise known as the mean, is given as follows:

 

E(X) = np

 

        = 15(0.25)

 

        = 3.75

 

Interpreting this result, we can expect to win approximately 4 out of the 15 hands.