Michael J. answered 11/19/17
Tutor
5
(5)
Effective High School STEM Tutor & CUNY Math Peer Leader
I will do the first one for you.
Find the indefinite integral first. We can easily integrate the 1st and last terms using the power rule.
(1/6)x6 - ∫5x dx + (5/2)x2
We need to find the integral of the middle term using some other techniques.
Let u = 5x
x = (1 / ln5)(lnu)
dx = du / uln(5)
Substituting,
∫udu / (uln5) =
∫1 / (ln5) du =
(1 / ln(5)) u =
5x / ln(5)
Lets check this integral to see if we get back the sub-integrand.
(5x ln5) (ln5) / (ln5)2
It checks. Therefore,
∫5x dx = 5x / ln(5)
So your definite integral is
[(1/6)(1)6 - (5 / ln5) + (5/2)(1)2] - [(1/6)(0)6 - (1 / ln5)] =
(1/6) - (5 / ln5) + (5/2) + (1 / ln5) =
-(4 / ln5) + (16 / 6) =
-(4 / ln5) + (8 / 3)
As for the second one, you should rewrite the radical as rational exponents. Then apply your integration techniques. SInce you did not use parenthesis to make it clear, I cannot answer this question for you.