
Andy C. answered 11/22/17
Tutor
4.9
(27)
Math/Physics Tutor
2x - 1
-------- > x + 4
x
2x - 1
------ - x - 4 > 0
x
let f(x) = (2x-1)/x - x- 4
We are interested in values of x
where f(x)>0
The zeros of this function are
(2x-1)/x - x - 4 = 0
(2x-1)/x = x+4
2x - 1 = x(x+4)
2x - 1 = x^2 + 4x
0 = x^2 + 4x - 2x + 1
0 = x^2 + 2x + 1
0 = ( x + 1 )( x + 1 )
x = -1
There is a vertical asymptope at x=-1
x< -1
-1 < x < 0
x>0
Examining the graph of f(x) or using sample test values,
f(x) > 0 when x<-1 or -1<x<0