Raymond B. answered 11/22/25
Math, microeconomics or criminal justice
R(t) = 0.1(t-1)^2 + 80
where t = years since 1990, R= Total Revenue in thousands of dollars
Annual Revenue = A(t) = .2(t-8)^2 + 30
in what year and month is Revenue at a maximum??
what was the max revenue per year??
find R' =0, solve for t
.2(t-1) = 0
t = 1
plug back into original equation for R(t)
R(1) = 80= max Total Revenue
= $80,000