Michael P. answered 01/26/18
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200 people total but 40 people do like any chocolate, therefore, include only total who like chocolate
TC = 200 - 40 = 160 people voted for some type of chocolate listed
TC = 200 - 40 = 160 people voted for some type of chocolate listed
Now assume:
A = number of people who only voted for one type of chocolate (either dark, milk, or white)
B = number of people who only voted for two types of chocolate
C = number of people who voted for all three types = 10
D = number of people who like at least two types of chocolate = B + C
dark chocolate votes = 120
milk chocolate votes = 100
white chocolate votes = 60
Therefore, total chocolate votes = A + 2*B + 3*C = 120 + 100 + 60 = 280
C= 10
A + 2*B + 3*(10) = 280
A + 2*B = 250
and A + B + C = 160 people voting for 1, 2, and 3 types of chocolate
A + B + 10 = 160
A + B = 150
Therefore, two eqns, two unknowns:
1) A + 2*B = 250
2) - [A + B = 150]
------------------------
0 + B = 100
A = 150 - B = 150 - 100 = 50
C = 10
D = B + C = 100 + 10 = 110 people like at least two types of chocolate
Michael P.
01/27/18