3(2z-1)-2(z+5)=2(z+1)

Question

6z-3-2z-10=2z+2 is this the first step in solving the equation? Im unsure how to continue to solve please help

Answer 1

Your first step is correct.  After using the distributive property, you have

6z - 3 - 2z - 10 = 2z + 2              Given problem after distributive property

6z - 2z - 3 - 10 = 2z + 2              Commutative property

4z - 13 = 2z + 2                         Simplify (6z - 2z = 4z, -3 -10 = -13)

4z - 13 - 2z = 2z + 2 - 2z            Subtract 2z from each side

4z - 13 - 2z = 0 + 2                    Inverse property of addition

4z - 13 -2z = 2                           Identity property of adddition

4z - 2z - 13 = 2                          Commutative property of addition

2z - 13 = 2                                Simplify (4z - 2z = 2z)

2z - 13 + 13 = 2 + 13                 Add 13 to each side

2z + 0 = 2 + 13                         Inverse property of addition

2z = 2 + 13                               Identity property of addition

2z = 15                                     Simplify (2 + 13 = 15)

2z/2 = 15/2                               Divide both sides by 2

1z = 15/2                                  Inverse property of multiplication

z = 15/2 or 7.5                           Identity property of multiplication