Find two consecutive integers such that twice the second minus the first is 75

Question

 Find two Consecutive integers. 

Answer 1

A good way to talk about two consecutive integers is to call the first one 'n', and the second 'n+1'. Then you can write an equation to represent what we're told here. Twice the second: 2(n+1), minus the first: - n, is 75. Thus:

 

2(n+1) - n  = 75

 

Can you solve it from there?