three consecutive odd integers such that three times the third is 21 less than two times the sum of the first and second

Question

I need help solving this problem. Is this correct?

replace first number with x.
replace second number with (x + 2)
replace third number with (x + 4)

your equation becomes:

2 * (x + x + 4) = x + 2 + 21

Answer 1

Let x = the smallest integer

Let x + 2 = the integer in the middle

Let x + 4 = the largest integer

3(x+4) = 2(x + x + 2) - 21

3x + 12 = 4x + 4 - 21

-x = -29

x = 29

x + 2 = 31

x + 4 = 33