Find the x intercepts from the standard form 3x^2+6x-9

Question

the equation is in standard form,change it to factored root form to find the x intercepts

Answer 1

3x^2+6x-9

 

Michael J. is correct.  You can also do "factor by grouping."

 

3(-9) = -27

Factors of -27 that add to 6:  9(-3)

Replace 6x with 9x - 3x and factor by grouping:

 

3x² + 9x - 3x -9

3x(x+3) -3 (x+3)

(3x-3)(x+3)

 

x = 1 or -3

Answer 2

Factor out 3 from the equation.

 

3(x² + 2x - 3) = 0

 

 

Factor completely.

 

3(x + 3)(x - 1) = 0

 

 

Now just set the factors equal to zero and solve for x.