Inactive Tutor answered 10/15/17
Tutor
New to Wyzant
F(x)=-1/2|x-1|+4 THIS IS NOT A QUADRATIC and as such it won't have a vertex
(2) y-intercept is when x=0; substitute & evaluate f(0)
(4) x-intercepts OCCUR whenever y = 0; that would be when |x-1|= 8; you can solve that!
(1) Axis of Symmetry is x=1
(2) Vertex
(2) y-intercept is when x=0; substitute & evaluate f(0)
(4) x-intercepts OCCUR whenever y = 0; that would be when |x-1|= 8; you can solve that!
(1) Axis of Symmetry is x=1
(2) Vertex