Find the equation of the line perpendicular to 4x+32y=128 and going through the point (-7,-4). Write your answer form y=mx+b

Question

Find the equation of the line perpendicular to 4x+32y=128 and going through the point (-7,-4). Write your answer form y=mx+b

Answer 1

4x+32y=128

32y= -4x+128

y= -4/32x + 128/32

y= -1/8 x +4

Slope of this line = -1/8

Slope of a perpendicular line = 8

Equation of a line passes thru (x₁, y₁) & slope m is

y-y₁ =m(x-x₁)

Equation of a line passes thru (-7,-4) & slope 8 is

y+4 =8(x+7)

y+4= 8x+56

y= 8x +52