
Mark C. answered 10/20/17
Tutor
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Patient tutor. Your success is my goal.
I would solve this with a matrix.
First, let x = minutes spent on the stationary bicycle
y = minutes spent on the stair climber
Next, take what's know - and make it into equations:
(1) Total minutes spent on both exercises: 30. So: x + y = 30
(2) Stationary bicycle burns 9 calories; stair climber burns 14.5 calories; total of 347 calories burned; so:
9x + 14.5y = 347
9x + 14.5y = 347
This gives us what we need for the initial tableau, for Iteration 0:
1 1 = 30
9 14.5 = 347
We want to get the value for 1x and 1y; so, we get the value in R2,C1 to become 0; which gives us the row operation of: -9R1 + R2 = new R2; which gives us the Iteration 1 matrix of:
1 1 = 30
0 5.5 = 77
Next, we want to get the value in R1,C2, to become 0;which gives us the row operation of: -2R2 + 11R1 = new R1; which gives us the Iteration 2 matrix of:
11 0 = 176
0 5.5 = 77
Next, we want to do row reductions, to get 1x = and 1y =; so:
(1/11)R1 = new R1
(1/5.5)R2 = new R2
This gives us the final matrix of:
1 0 = 16
0 1 = 14
This gives us (x,y) of (16,14); which means:
16 minutes on the stationary bicycle
14 minutes on the stair climber
To check our work, we plug these values into the 2 initial equations:
(1) 16 + 14 = 30 [Check]
(2) 9 * 16 + 14 * 14.5 = 347 [Check]