
Andrew M. answered 10/11/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Hi Karen;
First, what are we looking for? How many chickens did he start with?
Assign variables for the unknowns:
Let c = # chickens
Let d = # ducks
Now, from the information given make equations:
farmer had twice as many chickens as ducks :
c = 2d {equation 1}
After he sold 166 chickens and 29 ducks, he had half
as many chickens as ducks left:
c - 166 = (d-29)/2 {equation 2}
Since c=2d, substitute that into equation 2:
2d - 166 = (d-29)/2
multiply through by 2
4d - 332 = d - 29
on each side subtract d and add 332
3d = 303
d = 101 ducks
c = 2d = 202 chickens
Check: 202 - 166 = (101-29)/2
36 = 36
This checks as correct.