Word problem ,Algebra

Question

A waiter collected 150 coins from the tips she receives from her customers. The coins consist of nickels,dimes,quarters.
She has five more than twice the nickels in dimes and five more than four times the nickels in quarters .

1] How many coins of each kind does she have ?

2] How much money does the waiter have ?

Answer 1

Let x = the number of nickels

Let 2x + 5 = the number of dimes

Let 4x + 5 = the number of quarters

x + 2x + 5 + 4x + 5 = 150

7x = 140

x = 20 nickels

2x + 5 = 2(20) + 5 = 45 dimes

4x + 5 = 4(20) + 5 = 85 quarters

 

The waiter has 20(.05) + 45(.10) + 85(.25) = $17.75