
Kenneth S. answered 10/10/17
Tutor
4.8
(62)
Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
This is easy. Find the probability of 5 tosses of a fair coin landing Heads only once, or no times.
The answer will be 1 minus the sum of those two possibilities.
P(0 H) = 1/25 = 1/32
P(1 H) = 5(1/2)5 = 5/32
sum is 6/32 = 3/16
therefore P(more than 1 H in 5 tosses) = 1 - 3/16 = 13/16
Nala F.
10/10/17