Please anwer the below.

Question

If it snows on game day there is a 32% chance the Jets will win. If it does not snow on game day there is a 41% chance the jets will win. There is a 29% chance that it will snow on game day.

a. What is the probability the Jets will win?
b. What is the probability that it snows on game day and the Jets win?
c. What is the probability that it snows on game day given that the Jets win?

Answer 1

snow, then 32% chance jets win

no snow, then 41% chance jets win

29% chance it snows

what are odds jets win??

Pr(win) = weighted average = .29(.32)+(1-.29)((41) = .3839 = 38.39% chance Jets win

Pr(snows & jets win)=?? .29(.32) = .0928 = 9.28% chance it snows & jets win

Pr(snows/jets win)=?? use Bayes Theorem P(a)P(b/a) = P(b)P(a/b) with a=jets win, b=snows

P(b/a) = Pr(snows/jets win)=

P(b/a) = P(b)P(a/b)/P(a) = .29(.32)/.3839 = 0.2417296171... = about 24.17%