Given the cubic function : f (x)= (x-2) (x+2) (x-5), What are the zeros of the cubic function?

Question

Given the cubic function : f (x)= (x-2) (x+2) (x-5), What are the zeros of the cubic function?

 

Using the same function from #14, what is:

f(3)=

Answer 1

If x - a is a factor of a function then a is a zero.

f(x) = (x - 2)(x - (-2))(x - 5)

The zeros are, 2, -2, and 5

To determine f(3) substitute 3 for x  and and simplify