Write an equation for a line perpendicular to 4y+8x=12 and passing through the point (-6, 1)

Question

Write an equation for a line perpendicular to 4y+8x=12 and passing through the point (-6, 1)

Answer 1

4y + 8x = 12

 

        4y = -8x + 12

 

          y = -2x + 3    Slope = -2

 

Slope of perpendicular line = -1/(-2) = 1/2

 

Equation of perpendicular line:  y-1 = (1/2)(x-(-6))

 

                                                 y = (1/2)x + 4