The perimeter of a playing field for a certain sport is 238ft. The length is 47ft longer than the width. Find the dimensions

Question

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Answer 1

Apparently you have a rectangular field of perimeter 238 feet.

The perimeter of a rectangle is P = 2(L+w).

 

2(L+w) = 238

L+w = 119   {equation 1}

 

length is 47ft longer than the width:

L = w + 47   {equation 2}

 

Substitute w+47 in place of L in equation 1 and solve for w

 

w + 47 + w = 119

2w + 47 = 119

2w = 72

w = 36 ft

 

L = w + 47 = 83 ft

 

The field is 83 by 36 feet