Bisection Method help

Question

Let's say that I have a given function f(x):(x-1)(x-3)(x-5) with xlow=0 and xhigh=3.8

I know for the Bisection Method to work f(a) and f(b) must have opposite sign, but when i plug in xlow and xhigh they have the same sign. 

 

I also know that f(x) is continuous. How can I proceed doing the Bisection Method? 

Answer 1

There is more than one root

In that interval.

 

Try the following intervals:

(0,1.5)

(2.5,3.5)

(4.5,5.5)

They contain the roots

Of 1,3, and 5