Michael J. answered 09/27/17
Tutor
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Effective High School STEM Tutor & CUNY Math Peer Leader
lim 14 - 3x + 14x2 + 15
x→∞ _______ ____________
2 + x 25(3x - 1)2
You first realize that when you plug in x=∞, you get an indeterminate form. So you must rewrite the limit to eliminate that possibility. Since you are adding rationals, find the LCD and write as a single rational. LCD is 25(2 + x)(3x - 1)2.
The numerator is then written as
25(14 - 3x)(3x - 1)2 + (14x + 5)(2 + x)
Simplify this and divide it by the LCD. From there, divide the numerator and denominator by the highest power of x in the denominator. This will allow to use the concept 1/x=0 when x→∞. Then, plug in x=∞ to cancel out terms. In the end, your limit should be a constant value. If not, then a horizontal asymptote does not exist.