At an altitude of 3300 feet, the engine on a small plane fails. What angle of depression is needed to reach an airport runway that is 3 miles away by land? (Round your answer to the nearest tenth of a degree.)
plane

 3300 feet

 15,840 feet θ
 runway
The plane is 3miles*5280 feet per mile = 15,840 feet from the runway. The angle of depression, θ, is the angle from the runway to the plane along the hypotenuse of the triangle.
Tanθ = 3300/15840 = 0.01894
θ = tan^{1}(0.01894) = 6.31^{o}
Comments
c) 89.9°
d)12.8°