
Andy C. answered 09/24/17
Tutor
4.9
(27)
Math/Physics Tutor
(1) y = 8x + 16
x = 8y + 16 <--- x and y switch places
x-16 = 8y <--- solves for y0
(x-16)/8 = y
(2) f(g(x)) = 7 ( (1/7)x - 2) + 14 =
7 * (1/7) X - 14 + 14 =
[7 * (1/7)]X + (14 - 14) =
1X + 0 =
X
g(f(x)) = (1/7) ( 7x + 14) - 2
(1/7)(7x) + (1/7)(14) - 2
x + 2 - 2 =
x
(3) y = 5x is not an exponential function.
y = 5^x is an exponential function.
ln y = ln 5^x = x*ln 5
(4) log 7x = y
7x = 10^y
x = 10^y/7
(5) change of base formula : logA z = logB z / logB a
(6) x = log 390 ---> log390 = logE 390 / logE 10
= ln 390 / ln 10
Per Calculator log10 390 = 2.59106460703..... = ln 390/ln 10
x = 8y + 16 <--- x and y switch places
x-16 = 8y <--- solves for y0
(x-16)/8 = y
(2) f(g(x)) = 7 ( (1/7)x - 2) + 14 =
7 * (1/7) X - 14 + 14 =
[7 * (1/7)]X + (14 - 14) =
1X + 0 =
X
g(f(x)) = (1/7) ( 7x + 14) - 2
(1/7)(7x) + (1/7)(14) - 2
x + 2 - 2 =
x
(3) y = 5x is not an exponential function.
y = 5^x is an exponential function.
ln y = ln 5^x = x*ln 5
(4) log 7x = y
7x = 10^y
x = 10^y/7
(5) change of base formula : logA z = logB z / logB a
(6) x = log 390 ---> log390 = logE 390 / logE 10
= ln 390 / ln 10
Per Calculator log10 390 = 2.59106460703..... = ln 390/ln 10