Please explain how to simplify this expression

Question

x² - 6x + 5   ÷ 2x - 10

      3x^{2                   9x}

 

Answer 1

Is this two fractions?

 

(x²-6x+5)/3x² ÷ (2x-10)/9x

 

= [(x-5)(x-1)]/3x²]/[2(x-5)]/9x

 

Invert and multiply

 

= [(x-5)(x-1)]/3x²][9x/(2(x-5))]

 

The(x-5) in numerator and denominator cancel

 

= [(x-1)/3x²](9x/2)

 

3x in denominator divides into 9x² in numerator

leaving x in denominator and 3 in numerator.

 

= [(x-1)/x](3/2)

 

= 3(x-1)/2x