how many games would be played in a tournament of 6 friends if each person played every other person exactly once?

Question

i don't understand this at all.

Answer 1

If you're not sure of the formula you can look at the persons:

Call them A, B, C, D, E

 

Person A will play 5 other people

Person B will play 4 others (having already played A)

Person C will play 3 others (having already played A&B

Person D will play 2 others (having already played A,B,&C

Person E will play 1 other (having already played A,B,C,&D

Person F will play 0 others (having already played A,B,C,D,& E)

 

5+4+3+2+1+0 = 15 games

 

This kind of logic can be utilized on small totals like this.

Answer 2

no of person = 6

 

So total game played =(6(6-1))/2=6(5)/2 =30/2 =15