find tan ?

Question

if cos theta = -2 / sqrt 13 and sin theta = -3 / sqrt 13

Answer 1

cos(theta) = -2 / sqrt 13

sin(theta) = -3 / sqrt 13

 

with tan(x) = sin(x)/cos(x)

 

we get:

tan(theta) = (-3 / sqrt 13) / (-2 / sqrt 13) = 3/2