ok so i need help with fractions so here is one of them a-b/ a+b-2ab/ a^2-b^2

Question

algebra 2 fractions

Answer 1

(a-b)/(a+b) - 2ab/(a^2-b^2)

 

if we multipy the numerator and denominator of the first fraction by (a-b) this will give us a common denominator.

 

Always need to get a common denominator when adding or subtracting fractions.

 

So we get the following

 

(a-b)^2/(a^2-b^2) - 2ab/(a^2-b^2)

 

 

now expand the numerator of the first fraction and we get

 

(a² -2ab + b²) /(a² - b²)   - 2ab / (a² - b²) 

 

combine the numerators

 

(a² -4ab + b²)/(a² - b²)