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ok so i need help with fractions so here is one of them a-b/ a+b-2ab/ a^2-b^2

algebra 2 fractions

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I have couple of questions
1. are you sure that a+b-2ab is not a2+b2-2ab? If so the later can be written as (a-b)and a2-b2=(a+b)(a-b)
2. then the problem can be written as: (a-b)/((a+b)(a-b)3) and it is easy to see how to simplify
 
Jim
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1 Answer

(a-b)/(a+b) - 2ab/(a^2-b^2)
 
if we multipy the numerator and denominator of the first fraction by (a-b) this will give us a common denominator.
 
Always need to get a common denominator when adding or subtracting fractions.
 
So we get the following
 
(a-b)^2/(a^2-b^2) - 2ab/(a^2-b^2)
 
 
now expand the numerator of the first fraction and we get
 
(a2 -2ab + b2) /(a2 - b2)   - 2ab / (a2 - b2
 
combine the numerators
 
(a2 -4ab + b2)/(a2 - b2

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