algebra 2 fractions

(a-b)/(a+b) - 2ab/(a^2-b^2)

if we multipy the numerator and denominator of the first fraction by (a-b) this will give us a common denominator.

Always need to get a common denominator when adding or subtracting fractions.

So we get the following

(a-b)^2/(a^2-b^2) - 2ab/(a^2-b^2)

now expand the numerator of the first fraction and we get

(a

^{2}-2ab + b^{2}) /(a^{2 }- b^{2}) - 2ab / (a^{2}- b^{2})combine the numerators

(a

^{2}-4ab + b^{2})/(a^{2}- b^{2})
## Comments

^{2}+b^{2}-2ab? If so the later can be written as (a-b)^{2 }and a^{2}-b^{2}=(a+b)(a-b)^{3}) and it is easy to see how to simplify