Kenneth M.

asked • 09/04/17

how do you solve (−1+2i)(−2+3i)

how do you solve (−1+2i)(−2+3i)

Kenneth M.

how did you get the 6i2?
 
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09/04/17

Kenneth M.

actually how did you get this whole string? 2 - 4i - 3i + 6i2
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09/04/17

Mark M.

     -1 + 2i
     -2 + 3i
    -3i + 6i2
 2 -4i ____
 2 - 7i + 6i2
 2 - 7i -  6            (i2 = -1!)
-4 - 7i
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09/04/17

Mark M.

That's "long" multiplication. The lines did no show up.
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09/04/17

1 Expert Answer

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Mark M. answered • 09/04/17

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Solve is a direction to determine the value of the variable that makes an equation true. No equation, no variable, no solving!
The product:
(-1 + 2i)(-2 + 3i)
2 - 4i - 3i + 6i2
2 - 7i - 6
-4 - 7i
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Kenneth M.

thank you for explaining it. I appreciate the help.
 
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09/04/17

Mark M.

You are welcome. Glad that I could explain it for you. Look up the FOIL method for multiplying binomials. It is very helpful.
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09/04/17

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