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# One-tenth of the cars in a car park are yellow. Another car arrives and now one-ninth of the cars are yellow. How many cars are now in the car park?

One-tenth of the cars in a car park are yellow. Another car arrives and now one-ninth of the cars are yellow. How many cars are now in the car park?

Let No.of yellow cars = x amd Total Cars = Y
Then X/Y = 1/10  => 10X = Y
Since the ratio got increased after the car arrival, it must be an yellow car.
So Yellow cars = X+1 and Total Car = Y+!
(X+1)/(Y+1) = 1/9   =>  9X+9 = Y+1
So 9X + 9 = 10X + 1    => X = 8 and Y= 80
Total Cars will be Y+1 now = 81

### 1 Answer by Expert Tutors

Don L. | Fifteen years teaching and tutoring basic math skills and algebraFifteen years teaching and tutoring basi...
5.0 5.0 (2 lesson ratings) (2)
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Hi Jasun, let x represent the number of cars originally in the car park. Since 1/10 x is yellow, x must be divisible by 10. Examples 10, 20, ... 1000.

When 1 is added to x, x + 1, the number must be divisible by 9. Example, 80 + 1 = 81, and 81 is divisible by 9.

One answer is x + 1  = 81.

But that is not the only answer.

All multiples of 80 + n * 90, where n = 0, 1, 2, ...., are multiples which will satisfy the conditions of the question.

Example, n = 3, 80 + 270 = 350.

350 is divisible by 10.

Add 1 to 350 gives 351, which is divisible by 9.  351 / 9 = 39.

Therefore, 351 satisfies the question's requirements also.

Questions?