I'm confused onchow to solve inequalities graphically

Hi Karen,

Maybe this will help. Let's break it down into little pieces so bear with me! First, go by the DEFINITION of the absolute value.

|x| = x if its positive or -x if x is negative. So, lets consider something simple. |x| = 3. You know that x = 3 and -3. So, you know that when dealing with absolute values, there will be 2 solutions instead of 1.

Now I'm not limited to using the absolute value on a single variable x. I can also take the absolute value of somehting more complicated like k - 4. Replace x with k - 4.

|k - 4| = k - 4 and -(k-4). So, I have two solutions just like my simple example above. The rest of the problem states that |k-4| > 1 right? Well, if since |k-4| = k-4 then k-4 > 1 AND |k-4| = -(k-4) then -(k-4) > 1. We have two inequalities because the absolute value has two solutions.

Now, let's solve for k in both equations. You get k > 5 and k < 3. k is just a label for the real number line. The two inequalities say that |k - 4| > 1 will be true if k > 5 and k < 3. You draw the number line and cover the numbers greater than 5 and the numbers < 3 with a thick line. Since the inequality is just greater than, you have to show that k = 5 and 3 are NOT part of the solution. You can do this by starting the thick lines at open circles that lie at k = 3 and 5.

It was long but I want you to understand how the absolute value works. Hope it helps!

## Comments

An excellent explanation!

Your definition of absolute value is simple and exact. [k-4] = (k-4) AND -(k-4)>1 is the key. From that point on everything you say is right on the money! I especially like your explanation of use of open circles showing that k = 5 AND 3 are not included as part of the solution. GREAT WORK!