**the average of 3 numbers is 12. if one of the numbers is 8 what are the sum of the other 2 numbers i need help asap**

Let the variables X & Y represent the 2 missing numbers.

So, (8 + X + Y)/3 = 12

multiply both sides of the equation by 3 to get

**8 + X + Y = 36**subtract 8 from both sides of the equation to get

**X + Y = 28**So, the sum of the 2 missing numbers is

**28**!To check 8 + 28 = 36 and 36/3 = 12

Good luck!

Steve