write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation (2,-1);y =-2x +1

Question

(2,-1);y=-2x +1

 

Answer 1

y = -2x + 1

This is in slope intercept form. y = mx+b

Slope is m = -2

A perpendicular line has a slope that  is the

negative reciprocal of this.  m_p = -1/m

-1/(-2) = 1/2

 

You need the equation of the line through

(2, -1) with slope 1/2

 

y = (1/2)x + b

Using (2, -1) for (x, y), solve for b

 

-1 = (1/2)(2) + b

-1 = 1 + b

b = -2

 

your equation is:  y = (1/2)x - 2