Wnada M.

asked • 08/14/17

Assume the cards are drawn sequentially and without replacement

In how many ways can 5 diamonds be drawn from a standard deck of 52 cards?

Andy C.

CLARIFICATION:
 
 You are drawing cards without replacement.
  At first there are 13 diamonds (that is 13 cards of each suit)
 
  So you continue to draw cards until you observe a diamond. There are 13 possibilities.
  After the first diamond is observed, there are 12 diamonds remaining.
   After the second diamond is observed, there are 11 diamonds remaining.
 etc. etc. etc.
 
However, the ORDER of the diamonds is irrelevant.
 For example, 3,5,7,8,J of diamonds is the same set of observations as 5,8,3,J,7 of diamonds.
 
 So we need the (n choose k) formula which divides out these redundancies.
 (N choose k) = N!/ (k! (N-k)!)
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08/14/17

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