
Andy C. answered 08/08/17
Tutor
4.9
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Math/Physics Tutor
log (x(x-2) = 3
Raising to the power base 2
x(x-2) = 2^3
x^2 - 2x = 8
x^2 - 2x - 8 = 0
(x - 4)(x + 2) = 0
x-4 = 0 x+2 = 0
x=4 or x = -2
The solution x = -2 is disqualified
and rejected because the log of
a negative number is undefined.
check:
log 4 + log 2 = 2 + 1 = 3