Calculus derivative

Question

find mtan at point (2,2) on function y^3-x^2=4

 

 

i keep getting 0. Please help

Answer 1

by mtan  do you mean  slopeof the tangent to the curve?

 

3y²(y') -2x = 0

 

y'(2,2) = 2x/ (3y²) = 4/(12) = 1/3