let the 1st integer = x
the 2nd integer will be (x + 2)
x * (x + 2) = 4[x + (x + 2)] + 8
x² + 2x = 4(2x + 2) + 8
x² + 2x = 8x + 8 + 8
x² + 2x = 8x + 16
x² - 6x - 16 = 0
(x + 2)(x - 8) = 0
The only possible solution is x = 8 because the two integers are positive. Therefore, the first integer is 8, and the second integer is 10.