Deanna L. answered 06/11/14
Tutor
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Electrical engineering major and music lover with MIT degree
Here the population proportion is .5 and the survey sample proportion is 150/250=.6. To find our standard deviation, we find the square root of (p*(1-p) or .5 in this case.
Then our z test value is the difference between proportions (.1) times std dev (.5)/square root of users (250)=.003
making our p value: .51197
Since this is well above .05, we accept that the proportion of internet users paying online is greater than 50%.
Hope that helps,
Deanna