what would the height of the water be?

Question

if there is a cone with the dimensions of 10 as the height and 12 as the diameter, that is filled with water what would the height of the water be if it was poured into a rectangular prism with the dimensions of 8 as the length and 9 as the width

Answer 1

V=(1/3)∏r²h for a cone

V=(1/3)(3.14159)(6²)(10)

V=(1/3)(3.14159)(36)(10)

V=(1/3)(3.14159)(360)

V=(120)(3.14159)      (1/3)*360=120

V=376.99 cubic units

 

V=lwh for a rectangular prism

376.99=8*9*h

376.99=72*h

h=376.99/72

h=5.2359 units high