Mark M. answered 06/09/17
Tutor
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Mathematics Teacher - NCLB Highly Qualified
Sn = (n/2)(2a1 + (n - 1)d)
-114 = (12/2)(2a1 + 11(3)) - Solve for a1 and answer
Sn = (n/2)(a1 + an)
150 = (n/2)(13 + (-20)) - Solve for n, then
an = a1 + (n - 1)d
-20 = 13 + 19d - Solve for d and answer