Inactive Tutor answered 01/11/13
b2 + 5b + 6 = 0
This trinomial may be factored as the product of two binomials if we find two numbers such that:
- Their product is equal to 6, and
- Their sum is equal to 5
These two numbers indeed exist:
they are 3 and 2: (3)(2) = 6; and (3)+(2) = 5
Then our trinomial factors neatly: (b + 3)(b + 2) = 0
Now, since the product of the 2 binomials is 0, we assume that one or both are equal to 0:
b + 3 = 0 => b = -3
b + 2 = 0 => b = -2
Then b has two real solutions: -2 and -3.
It's a good habit to check your answers; it allows you to detect any mistakes and correct them before it's too late:
b2 + 5b + 6 = 0
* Let's check b = -3: (-3)2 + 5(-3) + 6 = 0 ???
9 - 15 + 6 = 0 Check!
* So far so good. Now b = -2: (-2)2 + 5(-2) + 6 = 0 ????
4 - 10 + 6 = 0 Check!!! we're correct! Let's move to the next problem. No problem!!