Need linear equation of a line that passes through (3,4)has slope of -4/3

The slope-intercept form of a straight line is:

y = mx + b

Where m is the slope and b is the y-intercept (the point (b,0)). In your problem, the slope is given to you and is -4/3, so the equation is:

y = (-4/3)x + b

To find b, plug the given point (3,4) into the equation:

y = (-4/3)x + b

4 = (-4/3)(3) + b [Plug in x = 3, y = 4)

Solve for b and you have your answer.