linear equation of a line that passes through (3,4) has slope of -4/3

Question

Need linear equation of a line that passes through (3,4)has slope of -4/3

Answer 1

The  slope-intercept form of a straight line is:

 

y = mx + b

 

Where m is the slope and b is the y-intercept (the point (b,0)).  In your problem, the slope is given to you and is -4/3, so the equation is:

 

y = (-4/3)x + b

 

To find b, plug the given point (3,4) into the equation:

 

y = (-4/3)x + b

 

4 = (-4/3)(3) + b                    [Plug in x = 3, y = 4)

 

Solve for b and you have your answer.