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linear equation of a line that passes through (3,4) has slope of -4/3

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1 Answer

The  slope-intercept form of a straight line is:
y = mx + b
Where m is the slope and b is the y-intercept (the point (b,0)).  In your problem, the slope is given to you and is -4/3, so the equation is:
y = (-4/3)x + b
To find b, plug the given point (3,4) into the equation:
y = (-4/3)x + b
4 = (-4/3)(3) + b                    [Plug in x = 3, y = 4)
Solve for b and you have your answer.