
Bob A. answered 05/09/14
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(-5ab4)3a-3b6
b-2
b-2
lets get rid of the denominator
1
b-2 is = b2
b-2 is = b2
so
= (-5ab4)3a-3b6b2 = (-5ab4)3a-3b8 = (-53a3b4·3)a-3b8 = -125a3a-3b12b8
= -125 b20