i need help on my homework.

Are you looking for confidence interval? i will assume so its usually 95 percent C.I which means Z of 1.96

mean + or _(Z) std/square root of the population(n)

280.90 +(1.96)123.70/sq root of 32

280-(1.96)123.70/sq root of 32

sq root of 32 is about 5.6

so 280.90+(1.96)123.70/5.6=324

280.90-(1.96)123.70/5.6=238

therefore my 95 percent confidence interval is in the range of 238-324 dollars in other words, I am 95 percent certain of this range ;)

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