Solve the system of linear equations

Question

4x+y-2z=0

2x-3y+3z=9

-6x-2y+z=0

Answer 1

 4X + Y - 2z = 0

 2X -3Y + 3Z = 9 

 -6X - 2Y + Z = 0

 

 

      4X +Y - 2Z = 0         0X  + 7 Y - 8Z = -18        4X + Y - 2Z = 0           4X  + Y -2Z = 0

-2 ( 2X - 3Y + 3Z = 9)   3(2X - 3 Y + 3Z) = 9     4 ( 0X -11y +10Z = 27 )   0X - 9Y +0Z = 18

      -6X  -2Y +Z = 0        -6X -2Y  + Z    =0       5 ( 0X  +7Y  -8Z  = -18)   0X +7Y -8Z  = -18

 

    4X + Y - 2Z = 0        4X + Y -2Z = 0          4X +0 Y +0Z = 3

    0X + Y + 0Z =-2       0X + Y+ 0Z =-2         0X + Y + 0Z  = -2

    0X + 0Y - 8Z = -4     0X  + 0Y +Z = 1/2     0X  + 0Y + Z = 1/2

 

     X = 3     Y = -2    Z = 1/2 are the answers: 

Following procedure:

  first eliminated X in both sides by multiplying 2nd equation by -2 and adding with first one

and 2nd equation by +3 and adding to 3rd one. The System reduces from 3 equation to 2 , and solve

then Y, and Z will be substituted to 1st equation and value of X will be calculated.