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# Tanner has \$6.25 in nickels and quarters. Suppose he has 11 more nickels than quarters. How many of each coin does he have?

Tanner has \$6.25 in nickels and quarters. Suppose he has 11 more nickels than quarters. How many of each coin does he have?

### 1 Answer by Expert Tutors

Lauren H. | Middle & High School MathMiddle & High School Math
5.0 5.0 (120 lesson ratings) (120)
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These were my favorite type of problems growing up because you can treat it like a puzzle!

So we know that Tanner has some number of nickels (n) and some number of quarters (q).
We know that he has 11 more nickels than quarters --> n=q+11  (more implies addition, always to whichever he has less of).
We also know that the total value is \$6.25.  The total value of his nickels is .05*n (since each nickel is worth 5 cents or \$0.05) and the total value of his quarters is .25*q (for the same reasoning.Therefore \$6.25=\$0.05*n+\$0.25*q.

Now we need to substitute q+11 for n since we know n is equal to q+11.

So \$6.25=\$0.05*(q+11)+\$0.25*q.

Solve this equation for q, the number of quarters.  Once you have q, go back to n=q+11 to find the number of nickels.

Hope this helps!