Tanner has $6.25 in nickels and quarters. Suppose he has 11 more nickels than quarters. How many of each coin does he have?

These were my favorite type of problems growing up because you can treat it like a puzzle!

So we know that Tanner has some number of nickels (n) and some number of quarters (q).

We know that he has 11 more nickels than quarters --> n=q+11 (more implies addition, always to whichever he has less of).

We also know that the total value is $6.25. The total value of his nickels is .05*n (since each nickel is worth 5 cents or $0.05) and the total value of his quarters is .25*q (for the same reasoning.Therefore $6.25=$0.05*n+$0.25*q.

Now we need to substitute q+11 for n since we know n is equal to q+11.

So $6.25=$0.05*(q+11)+$0.25*q.

Solve this equation for q, the number of quarters. Once you have q, go back to n=q+11 to find the number of nickels.

Hope this helps!