Damien C. answered • 05/26/17

A tutor who loves math and physics

Using n from 0 to 49 the expression would look like this

(1/50)Σ√(1+(1+n/50)^3)

Then it could be written

(1/50)Σ√(1+(50/50+n/50)^3) because 1=50/50

Or

(1/50)Σ√(1+((50+n)/50)^3)

If we put x=50+n then the limits will now be x=50+0=50 to 50+49=99

So we end up with

(1/50)Σ√(1+(x/50)^3) with x from 50 to 99. The two expressions are equivalent.

Hope that helps.