Damien C. answered 05/26/17
Tutor
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A tutor who loves math and physics
Using n from 0 to 49 the expression would look like this
(1/50)Σ√(1+(1+n/50)^3)
Then it could be written
(1/50)Σ√(1+(50/50+n/50)^3) because 1=50/50
Or
(1/50)Σ√(1+((50+n)/50)^3)
If we put x=50+n then the limits will now be x=50+0=50 to 50+49=99
So we end up with
(1/50)Σ√(1+(x/50)^3) with x from 50 to 99. The two expressions are equivalent.
Hope that helps.