Hello, thank you for taking the time to post your question!
The general formula you want to use to model this situation is
V(t) = P(1 – r)^t
where V(t) represents the value of the truck after t years
P is the principal or initial value of the truck, meaning $35,000
r is the annual rate of depreciation, meaning 0.20
t is the time in years
plugging in those values makes the equation
V(t) = 35000(1 – 0.20)^t
V(t) = 35000(0.80)^t
To solve for the second part then you would be using V(t) = 5000 and then solving for the value of t algebraically! When I do that using logarithms I end up getting 8.72 years for the value
I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)
Sierra M.
04/03/14